[SQL] [LeetCode] Challenge log 176

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176. Second Highest Salary

Use limit, offset, order by together

Write a SQL query to get the second highest salary from the Employee table.

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+----+--------+
| Id | Salary |
+----+--------+
| 1  | 100    |
| 2  | 200    |
| 3  | 300    |
+----+--------+

For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.

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+---------------------+
| SecondHighestSalary |
+---------------------+
| 200                 |
+---------------------+
Soulution:
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select ifnull(
(select distinct salary 
from Employee
order by salary desc
limit 1 offset 1), null) as SecondHighestSalary
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-- alter
select max(E.salary) as SecondHighestSalary
from Employee E
where E.salary !=
(
    select max(salary) as max
    from Employee
)
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